ISSN:
0945-3245
Source:
Springer Online Journal Archives 1860-2000
Topics:
Mathematics
Notes:
Abstract An efficient way to evaluate $$\sum\limits_{j = k}^n {( - 1)^{j - k - 1} \left( {\begin{array}{*{20}c} n \\ j \\ \end{array} } \right)\left( {\begin{array}{*{20}c} {j - 1} \\ {k - 1} \\ \end{array} } \right)} \ln j$$ is described. This sum, connected with the logarithmic Weibull distribution, is hard to evaluate directly, because the binomial coefficients become quite large, and then the alternating signs cause severe loss of significant figures. By converting the sum to an integral, we avoid this difficulty.
Type of Medium:
Electronic Resource
URL:
http://dx.doi.org/10.1007/BF01437221
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